Effects on g due to Depth D
Consider an object (of mass m) P at a depth d from the surface of the earth, R be the radius of the earth as shown in the figure below:
The acceleration due to gravity at the surface of Earth in terms of density is:
g = 4/3 x πρ x RG
At depth D,
gD = 4/3 x πρ x (R-D)G
On dividing both equations we get,
gd = g x πρ x (R-D)
Now two cases can be possible:
Case 1: If depth D is equal to the radius of the earth i.e. D = R, then:
gd = 0
Case 2: If depth D = 0, i.e. the object is at the surface of earth, then
gd = g
Acceleration due to Gravity
Acceleration due to gravity (or acceleration of gravity) or gravity acceleration is the acceleration caused by the gravitational force of attraction of large bodies. As we know that the term acceleration is defined as the rate of change of velocity with respect to a given time. Scientists like Sir Isaac Newton and Lord Henry Cavendish soon discovered that this increase in speed, or acceleration, was caused by a different force known as gravity by studying objects falling to the Earth in a variety of circumstances.
According to definitions, gravity is a force that pulls objects toward the center of mass, like the Earth. Conversely, acceleration describes how an object’s velocity or speed changes over time. Hence, the value of acceleration due to gravity is 9.8 m/s2 on earth.
Table of Content
- What is Acceleration due to Gravity?
- Acceleration due to Gravity Formula
- Units of Acceleration due to Gravity
- Derivation for the formula of acceleration due to gravity
- Calculation of the Value of Acceleration due to Gravity
- Factor affecting Acceleration due to Gravity
- Effects on g due to Height (h)
- Effects on g due to Depth D
- Effects on g due to Shape of Earth
- Effects on g due to the Rotation