2sinAcosB Formula

What is the Formula of 2sinAcosB?

The formula for 2sinAcosB is 2sinAcosB = sin(A + B) + sin(A – B).

What is 2SinACosB in Trigonometry?

2sinAcosB is an important trigonometric formulas that is used to solve various trigonometric identites.

What are Applications of 2sinAcosB?

Applications of 2sinAcosB formulas is, in simplifying and determining values of trigonometric expressions, integrals, and derivatives.



2sinAcosB Formula

2sinacosb is one of the important trigonometric formulas which is equal to sin (a + b) + sin (a – b). It is one of the product-to-sum formulae that is used to convert the product into a sum.

This formula is derived using the angle sum and angle difference formulas. Before learning more about the 2sinAsinB Formula, let’s first learn in brief about, Trigonometric Ratios

Table of Content

  • Trigonometric Ratios
  • 2sinAcosB Formula
  • Derivation of 2sinAcosB Formula
  • sin 2A Formula Using 2sinAcosB Formula
  • Problems on 2sinAcosB Formula
  • FAQs on 2sinAcosB Formula

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Trigonometric Ratios

Trigonometric ratios are ratios of sides in a triangle and there are six trigonometric ratios. In a right-angle triangle, the six trigonometric ratios are defined as:...

2sinAcosB Formula

2sinacosb is one of the product-to-sum formulae. Similarly, we have three other products to sum/difference formulas in trigonometry, namely, 2sinasinb, 2cosacosb, and 2cosasinb. By using the 2sinacosb formula, we can simplify trigonometric expressions and also solve integrals and derivatives involving expressions of the form 2sinacosb....

Derivation of 2sinAcosB Formula

From the sum and difference formulae of trigonometry, we have, sin (A + B) = sin A cos B + sin B cos A ⇢ (1)sin (A – B) = sin A cos B – sin B cos A ⇢  (2) Now, by adding equations (1) and (2) we get, ⇒ sin (A + B) + sin (A – B) = (sin A cos B + sin B cos A) + (sin A cos B – sin B cos A) ⇒ sin (A + B) + sin (A – B) = sin A cos B + sin A  cos B ⇒ sin (A + B) + sin (A – B) = 2 sin A  cos B Therefore, 2 sin A cos B = sin (A + B) + sin (A – B)...

sin 2A Formula Using 2sinAcosB Formula

We have, 2 sin A cos B = sin (A + B) + sin (A – B) Now, let us consider that A = B ⇒ 2 sin A cos A = sin (A + A) + sin (A – A) ⇒ 2 sin A cos A = sin 2A + sin 0° ⇒2 sin A cos A = sin 2A {Since sin 0° = 0} Hence, sin 2A = 2 sin A cos A...

Problems on 2sinAcosB Formula

Problem 1: Express 5 sin 2x cos 6x in terms of the sine function....

FAQs on 2sinAcosB Formula

What is the Formula of 2sinAcosB?...