Heron’s Formula Class 9
Heron’s Formula is a very valuable mathematical tool introduced in Class 9, to help students calculate the area of a triangle when the lengths of all three sides are known. This formula eliminates the need for height, making it especially useful for cases where the height is difficult to determine.
Heron’s formula is a practical and straightforward method for determining the area of triangles, enhancing geometric understanding among students at this level of class 9 mathematics.
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Heron’s Formula
Heron’s formula is a very popular formula for finding the area of a triangle when the three sides are given. This formula was given by “Heron” in his book “Metrica”. We can apply this formula to all types of triangles, be they right-angled, equilateral, or isosceles.
Heron’s formula, attributed to Heron of Alexandria around 62 CE, is used to calculate the area of a triangle based on the lengths of its sides. Expressed mathematically, if a, b, and c are the side lengths, then the area is given by: Area = A = √{s(s-a)(s-b)(s-c)} where s is the semi-perimeter of the triangle calculated as s = (a + b + c)/2
Let’s learn about Heron’s formula, definition of Heron’s Formula, Heron’s Formula expression, Heron’s Formula examples, and Heron’s Formula derivation in detail. We will also learn to apply Heron’s formula to different types of triangles.
Table of Content
- What is Heron’s Formula?
- Heron’s Formula Definition
- History of Heron’s Formula
- Proof of Heron’s Formula
- Heron’s Formula Derivation Using Pythagoras Theorem
- Heron’s Formula Derivation Using Cosine Rule
- How to Find the Area of Triangle Using Heron’s Formula?
- Heron’s Formula for Equilateral Triangle
- Heron’s Formula for Scalene Triangle
- Heron’s Formula for Isosceles Triangle
- Heron’s Formula for Area of Quadrilateral
- Applications of Heron’s Formula
- Area of Polygon using Heron’s Formula
- Heron’s Formula Class 9
- Heron’s Formula Examples