Implementation of XOR Gate from NOR Gate

Below is the logic diagram for implementation of XOR gate from NOR gate

Implementation of XOR gate from NOR gate

To implement XOR gate from NOR gate we follow below steps

  • First, we connect both the inputs in NOR gate resulting in (A + B)’.
  • Then, after we have another two NOR gates with the inputs A, (A + B)’ and B, (A + B)’ respectively with outputs [A + (A + B)’]’ and [B + (A + B)’]’.
  • Again, the connect outputs of the above NOR gates to next NOR gate resulting in the output [A’B + AB’]’.
  • Now, the result is generated in complement form so, we connect the result as the input for last NOR gate which gives the output [AB’ + A’B].
  • The resultant of the last NOR gate gives us XOR gate.
  • So, the number of NOR gates required to implement XOR gate is 5.

Implementation of XOR Gate from NOR Gate

Implementation of the XOR gate from the NOR gate is possible because the NOR gate is a Universal gate i.e., it can implement all other gates. The NOR gate gives the output 1 if all the inputs are 0. XOR gate is a logic gate that gives output 1 when several 1s are odd. In this article, we will explore the XOR gate, and NOR gate and implement the XOR gate from the NOR gate.

Table of Content

  • XOR Gate
  • NOR Gate
  • Implementation
  • Conclusion

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Implementation of XOR Gate from NOR Gate

Below is the logic diagram for implementation of XOR gate from NOR gate...

Conclusion

From the above discussion we can conclude that to implement XOR gate from NOR gate we require 5 NOR gates. In first NOR gate we connect both the inputs A and B. The expression for the XOR gate is given by A’B + AB’ whereas the expression for the NOR gate is (A + B)’....

Implementation of XOR Gate from NOR Gate – FAQs

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