Solved Example of 3-Phase Inverter
1. A single phase half bridge inverter has a resistance of 5 ohms and input DC voltage as 100V . Calculate
- the rms voltage occurring at the fundamental frequency
- output power
- peak current
- average current
- Harmonic rms voltage
- total harmonic distortion
Solution : Given R = 5 ohms , E = 100V
- The rms voltage occurring at the fundamental frequency E1RMS = 0.9 * 100 = 90v
- RMS output voltage = E0RMS = E = 100v
- output power = E^2 /R = (100)^2 / 5 = 2000W
- Peak current Ip = E0/R = 100/5 = 20A
- Average current = Ip/2 = 20/2 = 10A
- Harmonic RMS voltage En = { (E0RMS)^2 – (E1RMS)^2 }^0.5 = [(100)^2 – (90)^2]^0.5 = 43.588v
- Total harmonic distortion = En/E1RMS = 43.588/90 = 0.4843 * 100% = 48.43%
3-Phase Inverter
An inverter is a fundamental electrical device designed primarily for the conversion of direct current into alternating current . This versatile device , also known as a variable frequency drive , plays a vital role in a wide range of applications , including variable frequency drives and high power scenarios such as high voltage direct current (HVDC) power transmission. Its primary function is to control the torque and speed of electrical motors , making a vital role in many industrial and commercial settings. The versatility of inverters extends to their role in HVDC power transmission, where they are crucial in converting the DC power generated in power plants or offshore wind farms into AC power suitable for long transmission .
In this context , inverters help minimize energy losses and maximize the efficiency of electricity distribution over extensive distances. Here we will discuss about circuit design and working of inverter , types of inverters , advantages , limitations and applications of inverters .
Table of Content
- Three Phase Inverter
- Types
- Working
- Advantages
- Disadvantages
- Applications
- Solved Example