Solved Examples on Faraday’s Law of Electromagnetic Induction
Example 1: The magnetic flux linked with a coil is changed from 2Wb to 0.2Wb in 0.5 seconds. Calculate the induced emf.
Solution:
Δⲫ = 0.2-2 = 1.8wb
Δt = 0.5 sec
E = -(Δⲫ/Δt)
E= -1.8/0.5 volts
E= -3.6 volts
Therefore, induced emf will be -3.6 volts.
Example 2: In a coil of resistance 200, a current is induced by changing the magnetic flux through it as shown in the figure. Calculate the magnitude of change in flux through the coil.
Solution:
dq = – (N/R) dt
i = (1/R). (dq/dt)
Δⲫ = R.Δq
Δⲫ = 200 × (Area of circular graph)
Δⲫ = 200 × (1/2×20×0.5)
Δⲫ = 200 × 5
Δⲫ = 1000 Wb
Therefore, magnitude of change in flux is 1000 Wb.
Example 3: Calculate the emf induced in the wire. When a small piece of metal wire dragged across the gap between the pole pieces of a magnet in 0.6sec. The magnetic flux between the pole pieces is known to be 9×10-4 Wb.
Solution:
dt = 0.5 s
dⲫ = 9×10-4-0 = 9×10-4 Wb
E = (dⲫ)/dt
E= (9×10-4)/0.6
E= 0.0036 V
Therefore, the induced emf 0.0036V
Faraday’s Laws of Electromagnetic Induction
Faraday’s Law of Electromagnetic Induction is the basic law of electromagnetism that is used to explain the working of various equipment that includes an electric motor, electric generator, etc. Faraday’s law was given by an English scientist Michael Faraday in 1831. According to Faraday’s Law of Electromagnetic Induction, the induced current in the circuit is directly proportional to the rate of change of Magnetic Flux.
Let’s learn about Faraday’s Law of Electromagnetic Induction, its experiment, derivation, examples, and others in detail in this article.