Solved Examples on Ohm’s Law
Example 1: Find the resistance of an electrical circuit with a voltage supply of 15 V and a current of 3 mA.
Solution:
Given:
V = 15 V,
I = 3 mA = 0.003 A
The resistance of an electrical circuit is given as:
⇒ R = V / I
⇒ R = 15 V / 0.003 A
⇒ R = 5000 Ω
⇒ R = 5 kΩHence, the resistance of an electrical circuit is 5 kΩ.
Example 2: If the resistance of an electric iron is 10 Ω and a current of 6 A flows through the resistance. Find the voltage between two points.
Solution:
Given:
I = 6 A, R = 10 Ω
The formula to calculate the voltage is given as:
V = I × R
⇒ V = 6 A × 10 Ω
⇒ V = 60 VHence, the voltage between two points is 60 V.
Example 3: Find the current passing through the conductor drawing 20 volts when the power drawn by it is 60 watts.
Solution:
According to Ohm’s P = VI
Given P = 60 watt, V = 20 volt
⇒ I = P/V
⇒ I = 60/20
⇒ I = 3 AHence, the current flowing through the conductor is 3 A
Example 4: A battery of 6 V is connected to the bulb of resistance 4 Ω. Find the current passing through the bulb and the circuit’s power.
Solution:
Given,
V = 6 V
R = 4 ΩWe know that,
V = IR (Ohms Law)
⇒ 6 = 4R
⇒ I = 6 ÷ 4 = 1.5 A
⇒ I = 1.5 A
Thus, the current flowing through the bulb is 1.5 A
For the Power of the circuit
P = VI
⇒ P = (6)(1.5)
⇒ P = 9 watt
Thus, the power of the circuit is 9 watts.
Ohm’s Law
Ohm’s Law was given by German physicist Georg Simon Ohm. It states the relationship between current, resistance, and voltage across an electrical circuit. This relationship between current I, voltage V, and resistance R was given by famous German scientist Georg Simon Ohm in 1827. He found conducting his experiment that the product of the current flowing through the conductor and the resistance of the conductor determines the voltage drop over that conductor in the circuit.
In this article, we will explore the concept of Ohm’s Law in detail including all the topics mentioned in the following table of content.