How to use the Array.sort() Method In Typescript
The Array.sort() method allows us to sort arrays based on a provided comparator function. We can define a custom comparator function that compares the desired properties of objects and sorts them accordingly.
Example: The below code uses a simple comparator function to sort an array of objects.
interface MyObject {
id: number;
name: string;
}
const objects: MyObject[] = [
{ id: 2, name: 'Object B' },
{ id: 1, name: 'Object A' },
{ id: 3, name: 'Object C' }
];
objects.sort((a, b) => a.id - b.id);
console.log(objects);
Output:
[
{ id: 1, name: 'Object A' },
{ id: 2, name: 'Object B' },
{ id: 3, name: 'Object C' }
]
How to Sort Objects in an Array Based on a Property in a Specific Order in TypeScript ?
Sorting objects in an array based on a specific property is a common task in software development. TypeScript, with its static typing and powerful features, provides various approaches to accomplish this task efficiently. The below approaches can be used to sort an array of objects in properties.
Table of Content
- Using the Array.sort() Method
- Using the localeCompare() Method for Strings