Volume of the Combination of Solids
As volume refers to the capacity or the space occupied, we can infer that the volume of the combination of solids is equal to the sum of the volume of the simple solids. This was not the case with surface areas, where some part of the simple solid, gets hidden.
Volume of the combination of the solids = volume of the simple solid 1 + volume of the simple solid 2 + volume of the simple solid 3 + …
Example: Given an ice cream cone, as shown below. The total height of the ice cream cone is 7cm, and the width is 6cm. Find the volume of the ice cream cone.
Solution:
We can observe that,
The ice cream cone is made of 2 simple solids i.e. a cone and a hemisphere.
Volume of ice cream cone = volume of cone + volume of hemisphere,
Given,
Raidus of the hemisphere and base of the cone = r = 3cm,
Height of cone = Total height of solid – radius of the hemisphere = h = 7 – 3 = 4cm,
Volume of hemisphere = 2/3πr3 = 2/3.π.33 = 18π cm2,
Volume of cone = 1/3πr2h = 1/3π324 = 12π cm2,
Volume of ice cream cone = 18π + 12π = 30π cm2.
Surface Areas and Volumes Class 10 Maths Notes Chapter 13
CBSE Class 10 Maths Notes Chapter 13 Surface Areas and Volumes are an excellent resource, for knowing all the concepts of a particular chapter in a crisp, and friendly manner. Our articles, help students learn in their language, with proper images, and solved examples for better understanding the concepts.
Chapter 13 of the NCERT Class 10 Maths textbook delves into the world of Surface area and volume and covers various topics such as understanding the CSA, TSA of combined solids, volume of combined solids, converting from one solid to another solid, and the volume of the frustum. Notes are designed to give students a comprehensive summary of the entire chapter and include all the essential topics, formulae, and concepts needed to succeed in their exams.