What is the Sum of Squares of ‘n’ Natural Numbers?
The sum of squares of ‘n’ natural numbers is the sum of squares of all natural numbers. Its formula is, Sum = 12 + 22 + 32 + … + n2 = [n(n+1) (2n+1)]/6. The sum of Squares of First ‘n’ Natural Numbers is represented as Sn and the formula for the same is added in the image below:
Sum of Squares of n Natural numbers
Sum of Squares of n Natural numbers: The sum of squares of n natural numbers is calculated using the formula [n(n+1)(2n+1)] / 6 where ‘n’ is a natural number. There are formulas for calculating the sum of squares of first n even numbers as well as first n odd numbers.
In this article, we have covered the sum of squares of the ‘n’ natural number formula, its sum of squares proof, related examples, and others in detail.
Table of Content
- What is the Sum of Squares of ‘n’ Natural Numbers?
- Sum of Squares of n Natural Numbers Formula
- Sum of Squares of Natural Numbers Proof
- Sum of Squares of Even and Odd Natural Numbers
- Sum of Squares of Even Natural Numbers
- Sum of Squares of Odd Natural Numbers
- Sum of Squares of Two and Three Natural Numbers
- Sum of Squares in Geometry
- Sum of Squares of n Natural Numbers Solved Questions
- Practice Questions on Sum of Squares of n Natural Numbers