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C # tutorial
With method overloading, multiple methods can have the same name with differentparameters
With method overloading, multiple methods can have the same name with different parameters:
int myMethod(int x)
float myMethod(float x)
double myMethod(double x, double y)
Consider the following example, which has two methods that add numbers of different type:
static int plusMethodInt(int x, int y) {
return x + y;
}
static double plusMethodDouble(double x, double y) {
return x + y;
}
public static void main(String[] args) {
int myNum1 = plusMethodInt(8, 5);
double myNum2 = plusMethodDouble(4.3, 6.26);
System.out.println("int: " + myNum1);
System.out.println("double: " + myNum2);
}
Instead of defining two methods that should do the same thing, it is better to overload one.
In the example below, we overload the plusMethod
method to work for both int
and double
:
static int plusMethod(int x, int y) {
return x + y;
}
static double plusMethod(double x, double y) {
return x + y;
}
public static void main(String[] args) {
int myNum1 = plusMethod(8, 5);
double myNum2 = plusMethod(4.3, 6.26);
System.out.println("int: " + myNum1);
System.out.println("double: " + myNum2);
}
Note: Multiple methods can have the same name as long as the number and/or type of parameters are different.